|
|
|
|
||
|
|
|
|
|
The
Quadratic Formula:
I not only cannot apply the Quadratic Formula at this point, I cannot factor either. I can not claim that "x = 4, x – 2 = 4", because this is not how "solving by factoring" works. I must first rearrange the equation in the form "(quadratic) = 0", whether I'm factoring or using the Quadratic Formula. The first thing I have to do here is multiply through on the left-hand side, and then I'll move the 4 over: x(x
– 2) = 4 Since there are no factors of (1)(–4) = –4 that add up to –2, then this quadratic does not factor. (In other words, there is no possible way that the faux-factoring solution of "x = 4, x – 2 = 4" could be even slightly correct.) So factoring won't work, but I can use the Quadratic Formula; in this case, a = 1, b = –2, and c = –4: Copyright © Elizabeth Stapel 2006-2008 All Rights Reserved
Then the answer is: x = –1.24, x = 3.24, rounded to two places.
There is a connection between the solutions from the Quadratic Formula and the graph of the parabola: you can tell how many x-intercepts you're going to have from the value inside the square root. The argument of the square root, the expression b2 – 4ac, is called the "discriminant" because, by using its value, you can discriminate between (tell the differences between) the various solution types.
Using a = 9, b = 12, and c = 4, the Quadratic Formula gives:
Then the answer is x = –2/3 In the previous examples, I had gotten two solutions because of the "plus-minus" part of the Formula. In this case, though, the square root reduced to zero, so the plus-minus didn't count for anything. This solution is called a "repeated" root, because x is equal to –2/3, but it's equal kind of twice: –2/3 + 0 and –2/3 – 0. You can also see this repetition better if you factor: 9x2 + 12x + 4 = (3x + 2)(3x + 2) = 0, so x = –2/3 and x = –2/3. Any time you get zero in the square root of the Quadratic Formula, you'll only get one solution. The square-root part of the Quadratic Formula is called "the discriminant", I suppose because you can use it to discriminate between whether the given quadratic has two solutions, one solution, or no solutions.
The parabola only just touches the x-axis at x = –2/3; it doesn't actually cross. This is always true: if you have a root that appears exactly twice, then the graph will "kiss" the axis there, but not pass through.
Since there are no factors of (3)(2) = 6 that add up to 4, this quadratic does not factor. But the Quadratic Formula always works; in this case, a = 3, b = 4, and c = 2:
At this point, I have a negative number inside the square root. If you haven't learned about complex numbers yet, then you would have to stop here, and the answer would be "no solution"; if you do know about complex numbers, then you can continue the calculations:
If you do not know about complexes, then your answer would be "no solution". If you do know about complexes, then you would say there there is a "complex solution" and would give the answer (shown above) with the " i " in it. But whether or not you know about complexes, you know that you cannot graph your answer, because you cannot graph the square root of a negative number. There are no such values on the x-axis. Since you can't find a graphable solution to the quadratic, then reasonably there should not be any x-intercept (because you can graph an x-intercept).
This relationship is always true: If you get a negative value inside the square root, then there will be no real number solution, and therefore no x-intercepts. (The relationship between the value inside the square root, the type of solutions, and the number of x-intercepts on the graph is summarized in a chart on the next page.) << Previous Top | 1 | 2 | 3 | Next >>
|
|
|
|
Copyright © 2000-2009 Elizabeth Stapel | About | Terms of Use |
|
|
|
|
|
|